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# Which shows one way to determine the factors of x^{3} + 4x^{2} + 5x + 20 by grouping?

x(x^{2} + 4) + 5(x^{2} + 4)

x^{2}(x + 4) + 5(x + 4)

x^{2}(x + 5) + 4(x + 5)

x(x^{2} + 5) + 4x(x^{2} + 5)

**Solution:**

It is given that

x^{3} + 4x^{2} + 5x + 20

Here we should find the factors by grouping

It is done by taking out the greatest common factor which is common from different terms.

We can take x^{2} common from the first two terms and 5 common from the last two terms

x^{3} + 4x^{2} + 5x + 20

= x^{2} (x + 4) + 5 (x + 4)

= (x^{2} + 5) (x + 4)

Therefore, the factors are x^{2}(x + 4) + 5(x + 4).

## Which shows one way to determine the factors of x^{3} + 4x^{2} + 5x + 20 by grouping?

x(x^{2} + 4) + 5(x^{2} + 4)

x^{2}(x + 4) + 5(x + 4)

x^{2}(x + 5) + 4(x + 5)

x(x^{2} + 5) + 4x(x^{2} + 5)

**Summary:**

x^{2}(x + 4) + 5(x + 4)is a way to determine the factors of x^{3} + 4x^{2} + 5x + 20 by grouping.

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