Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Solution:

A progression is a sequence of numbers that follow a specific pattern.

An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same.

In an arithmetic progression, there is a possibility to derive a formula for the n^th term.

Given,

a = -10 and common difference, d = -2

Therefore,

First term = a = -10

Second term = a + d = -10 -2 = -12

Third term = a + 2d = -10 + [2 × (-2)] = -14

Fourth term = a + 3d = -10 + [3 × (-2)] = -16

Fifth term = a + 4d = -10 + [4 × (-2)] = -18

Sixth term = a + 5d = -10 + [5 × (-2)] = -20

Seventh term = a + 6d = -10+[6×(-2)] = -22

Eighth term = a + 7d = -10 + [7 × (-2)] = -24

Ninth term = a + 8d = -10 + [8 × (-2)] = -26

Tenth term = a + 9d = -10 + [9 × (-2)] = -28

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Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

Summary:

The first ten terms of a sequence whose first term is -10 and whose common difference is -2 are; -10, -12, -14, -16, -18, -20, -22, -24, -26, -28.