a = 1/2 , d = -1/6, write the first three terms of the AP

Solution:

An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same.

We know that,

The first three terms of AP can be expressed as :

a, a + d, a + 2d.

1/2, 1/2 + (-1/6), 1/2 + 2 (-1/6)

1/2, 1/3, 1/6

The first three terms of the given arithmetic progression are 1/2, 1/3, 1/6.

Therefore, the first three terms of the given arithmetic progression are 1/2, 1/3, 1/6.

✦ Try This: The 10^th and 18^th terms of an A. P. are 41 and 73 respectively. Find 26^th term

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5

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NCERT Exemplar Class 10 Maths Exercise 5.3 Problem 3 (i)

a = 1/2 , d = -1/6, write the first three terms of the AP

Summary:

The first three terms of the APs when a and d are a = 1/2 , d = -1/6 is 1/2, 1/3, 1/6

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☛ Related Questions:

• a = -5, d = -3, write the first three terms of the AP
• a =√2, d = 1/√2, write the first three terms of the AP
• Find a, b and c such that the following numbers are in AP: a, 7, b, 23, c