a =√2, d = 1/√2, write the first three terms of the AP
Solution:
An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same.
We know that,
The first three terms of AP can be expressed as :
a, a + d, a + 2d
√2, √2+1/√2, √2+2/√2
√2, 3/√2, 4/√2
The first three terms of the given arithmetic progression are √2, 3/√2, 4/√2.
Therefore, the first three terms of the given arithmetic progression are √2, 3/√2, 4/√2.
✦ Try This: If the 3rd term of an A.P. is 6 and 5th term of that A.P. is 12. Then find the 21st term of that A.P
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5
NCERT Exemplar Class 10 Maths Exercise 5.3 Problem 3 (iii)
a =√2 , d = 1/√2, write the first three terms of the AP
Summary:
An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same. The first three terms of the APs when a and d are are a =√2 , d = 1/√2 is √2, 3/√2, 4/√2
☛ Related Questions:
- Determine the AP whose fifth term is 19 and the difference of the eighth term from the thirteenth te . . . .
- The 26th, 11th and the last term of an AP are 0, 3 and -⅕ respectively. Find the commondifference an . . . .
- The sum of the 5th and the 7th terms of an AP is 52 and the 10th term is 46. Find the AP
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