a = -5, d = -3, write the first three terms of the AP

Solution:

An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same.

We know that,

The first three terms of AP can be expressed as :

a, a + d, a + 2d

Substituting the values

-5, -5 + 1 (-3), - 5 + 2 (-3)

-5, -8, -11

The first three terms of the given arithmetic progression are - 5, - 8, - 11.

Therefore, the first three terms of the given arithmetic progression are - 5, - 8, - 11

✦ Try This: If an A.P. is 3,5,7,9……. Find the 12th term of the A.P

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 5

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NCERT Exemplar Class 10 Maths Exercise 5.3 Problem 3 (ii)

a = -5, d = -3, write the first three terms of the AP

Summary:

The first three terms of the APs when a and d are a = -5, d = -3 is - 5, - 8, - 11

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☛ Related Questions:

• Find a, b and c such that the following numbers are in AP: a, 7, b, 23, c
• Determine the AP whose fifth term is 19 and the difference of the eighth term from the thirteenth te . . . .
• The 26th, 11th and the last term of an AP are 0, 3 and -⅕ respectively. Find the commondifference an . . . .