# A three-digit number 42x is divisible by 9. Find the value of x.

**Solution: **

A __number__ is divisible by 9 if the sum of its digits is 9 or any number divisible by 9.

So if the number 42x has to be divisible by 9 then 4 + 2 + x = 9 or any number divisible by 9.

Hence x = 9 - 6 = 3. Therefore the number will be 423.

The next number divisible by 9 is 18. Therefore

4 + 2 + x = 18

x = 18 - 6 = 12

The digit x cannor be two digit hence the three digit number divisible by 9 will be 423.

**✦ Try This: **A three digit number 1x3 is divisible by 11. Find the value of x.

For a number to be divisible by 11 the condition is that the difference of the sum of alternative digits is either zero or is divisible by 11.

x - (1 + 3) = 0

x = 4

Alternatively

x - (1 + 3) = 11

x = 11 + 4 = 15

But x cannot be two digits. Hence,

The three digit divisible by 11 is 143.

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 16

**NCERT Exemplar Class 8 Maths Chapter 13 Sample Problem 11**

## A three-digit number 42x is divisible by 9. Find the value of x.

**Summary:**

A three-digit number 42x is divisible by 9. The value of x is 3.

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