# Suppose that the division x ÷ 5 leaves a remainder 4 and the division x ÷ 2 leaves a remainder 1. Find the ones digit of x.

**Solution:**

A __number__ when divided by 5 leaves a remainder 4 has to end in 4 or 9. Similarly a number divided by 2 leaves a __remainder__ 1 can end in 3, 5, 7 and 9. The number common to both is number ending in 9.

For example 29 when divided 5 will give 4 and when divided by 2 will give remainder of 1.

Hence when x divided by 5 and 2 respectively leaves remainder 4 and 1 respectively, x’s ones digit is 9.

**✦ Try This: **Suppose that the division x ÷ 7 leaves a remainder 6 and the division x ÷ 4 gives the remainder 3, find the ones digit of x.

If x divided by 7 leaves a remainder 6 implies that the number ends with 0, 1, 2, 3, 4, 5, 7, 8, and 9 when x divided by 4 gives a remainder of 3 implies the number can end with 1, 3, 5, 7 or 9. The common digits are 1, 3, 5, 7 and 9. Hence the ones digit of number x can be 1, 3, 5, 7 and 9.

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 16

**NCERT Exemplar Class 8 Maths Chapter 13 Sample Problem 13**

## Suppose that the division x ÷ 5 leaves a remainder 4 and the division x ÷ 2 leaves a remainder 1. Find the ones digit of x.

**Summary:**

The division x ÷ 5 leaves a remainder 4 and the division x ÷ 2 leaves a remainder 1. The ones digit of x should be 9.

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