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# By selling 50 pens, a shopkeeper lost the amount equal to the selling price of 10 pens. His loss per cent is __________

**Solution :**

Let the selling price(SP) of each pen be x. Therefore the selling price of 50 pens will be :

Selling Price of 50 pens = 50x

By selling at x the shopkeeper makes a loss of selling price of 10 pens which is equal to :

Loss made by selling 50 pens for x = 10x

Therefore,

SP of 50 pens - CP of 50 pens = Selling price of 10 pens

Since it is a loss we can write:

50x - CP = -10x

Therefore Cost Price(CP) of 50 pens = 50x + 10x = 60x

Loss % = [(SP - CP)/CP] × 100

= [(50x - 60x)/60x] × 100

= [10x/60x] × 100

= (1/6) × 100

= 50/3%

**✦ ****Try this**: By selling 60 pens, a shopkeeper lost the amount equal to the selling price of 15 pens. His loss per cent is __________.

If selling price of a pen is x then the loss on selling 60 pens is 15x

Loss = SP of 60 pens - Cost Price of 60 Pens = -(SP of 15 pens)

CP of 60 pens = SP of 60 pens + SP of 15 pens

= 60x + 15x = 75x

Loss % = [15x/75x] × 100 = 20%

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 8

**NCERT Exemplar Class 8 Maths Chapter 9 Sample Problem 5**

## By selling 50 pens, a shopkeeper lost the amount equal to the selling price of 10 pens. His loss per cent is __________

**Summary:**

By selling 50 pens, a shopkeeper lost the amount equal the selling price of 10 pens. His loss percent is 50/3%

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