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# Construct a triangle PQR such that PQ = 6 cm, QR = 7 cm and PR = 4.5 cm

**Solution:**

Steps of Construction:

1. Construct a line PQ of length 6 cm.

2. Taking P as centre, construct an arc of 4.5 cm radius.

3. Taking Q as centre, construct an arc of 7 cm radius which intersects the previous arc at the point R.

4. Now join PR and QR.

Therefore, triangle PQR is the required triangle.

**✦ Try This: **Construct a triangle ABC such that AB = 5 cm, BC = 6 cm and AC = 3.5 cm

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 14

**NCERT Exemplar Class 7 Maths Chapter 12 Sample Problem 13**

## Construct a triangle PQR such that PQ = 6 cm, QR = 7 cm and PR = 4.5 cm

**Summary:**

A triangle PQR such that PQ = 6 cm, QR = 7 cm and PR = 4.5 cm is constructed.

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