# Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig. 8.19). Show that

i) it bisects ∠C also, ii) ABCD is a rhombus

**Solution:**

Given: The diagonal AC of a parallelogram ABCD bisects ∠A.

We can use alternate interior angles property to show that the diagonal AC bisects ∠C and by showing all sides are equal, it can be proved ABCD is a rhombus.

i) ABCD is a parallelogram.

∠DAC = ∠BCA (Alternate interior angles) ....................(1)

∠BAC = ∠DCA (Alternate interior angles) ....................(2)

However, it is given that AC bisects ∠A.

∠DAC = ∠BAC ....................(3)

From equations (1), (2), and (3), we obtain

∠DCA = ∠BAC = ∠DAC = ∠BCA ....................(4)

Thus, ∠DCA = ∠BCA

Hence, AC bisects ∠C.

ii) From Equation (4), we obtain

∠DAC = ∠DCA

DA = DC (Side opposite to equal angles are equal)

However, DA = BC and AB = CD (Opposite sides of a parallelogram are equal)

Thus, AB = BC = CD = DA

Hence, ABCD is a rhombus.

**Video Solution:**

## Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig. 8.19). Show that i) It bisects ∠C also, ii) ABCD is a rhombus

### NCERT Maths Solutions Class 9 - Chapter 8 Exercise 8.1 Question 6:

**Summary:**

If diagonal AC of a parallelogram ABCD bisects ∠A, then it bisects ∠C, and also it is proved that ABCD is a rhombus.