# Find the area enclosed in Fig. 9.46

**Solution:**

The figure represents a __semicircle__ and rectangle

We have to find the area enclosed by the figure.

__Area of semicircle__ = πr²/2

Where, r is the __radius of the circle__

From the figure,

diameter = 10.2 - 3.9 = 6.3 cm

Radius = 6.3/2 = 3.15 cm

Area of semicircle = (22/7)(3.15)²/2

= (11/7)(3.15)²

= 15.59 cm²

__Area of rectangle__ = length × breadth

= 10.2 × 1.5

= 15.3 cm²

Area enclosed by the figure = area of semicircle + area of rectangle

= 15.59 + 15.3

= 30.89 cm²

Therefore, the area enclosed by the figure is 30.89 cm²

**✦ Try This:** If two identical rectangles of perimeter 30 cm are joined together, then the perimeter of the new shape will be equal to ____ cm.

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 94**

## Find the area enclosed in Fig. 9.46

**Summary:**

The area enclosed by the figure is 30.89 cm²

**☛ Related Questions:**

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