Learn Find The Area Enclosed In Fig 9 47

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# Find the area enclosed in Fig. 9.47

**Solution:**

The figure represents a rectangle and a triangle

We have to find the area enclosed by the figure.

__Area of rectangle__ = length × breadth

= 13 × 4

= 52 cm²

__Area of triangle__ = 1/2 × base × height

Base = 13 - 8 = 5 cm

Height = 16 - 4 = 12 cm

Area of triangle = 1/2 × 5 × 12

= 5(6)

= 30 cm²

Area enclosed by the figure = area of triangle + area of rectangle

= 30 + 52

= 82 cm²

Therefore, the area enclosed by the figure is 82 cm²

**✦ Try This: **The perimeter of a rhombus is 100 cm and one diagonal is 10 cm long then the length of the other diagonal is

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 95**

## Find the area enclosed in Fig. 9.47

**Summary:**

The area enclosed by the figure is 82 cm²

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