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# Find the area of the quadrilateral ABCD. Here, AC = 22 cm, BM = 3 cm, DN = 3 cm, and BM ⊥ AC, DN ⊥ AC

**Solution:**

Given: AC = 22 cm, BM = 3 cm, DN = 3 cm

Area of the ∆ ABC = 1/2 × base × height

= 1/2 × AC × BM

= 1/2 × 22 cm × 3 cm

= 33 cm^{2}

Area of the ∆ ADC = 1/2 × base × height

= 1/2 × AC × DN

= 1/2 × 22 × 3

= 33 cm^{2}

Area of the quadrilateral ABCD = Area of the ∆ ABC + Area of the ∆ ADC

= 33 cm^{2} + 33 cm^{2}

= 66 cm^{2}

**☛ Check: **NCERT Solutions Class 7 Maths Chapter 11

**Video Solution:**

## Find the area of the quadrilateral ABCD. Here, AC = 22 cm, BM = 3 cm, DN = 3 cm, and BM ⊥ AC, DN ⊥ AC

Maths NCERT Solutions Class 7 Chapter 11 Exercise 11.4 Question 11

**Summary:**

The area of the quadrilateral ABCD is 66 cm^{2}. Given, AC = 22 cm, BM = 3 cm, DN = 3 cm, and BM ⊥ AC, DN ⊥ AC.

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