# Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2

**Solution:**

The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂_{ - }x₁)^{2} + (y₂ - y₁)^{2}]

Let the points be A(0, 0) and B(36, 15)

Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15

We know that the distance between the two points is given by the Distance Formula,

= √ [(x₂_{ - }x₁)^{2} + (y₂ - y₁)^{2}]....(1)

= √ (36 - 0)^{2} + 15 - 0)^{2}

= √ [(1296) + (225)]

= √1521

= 39

Yes, it is possible to find the distance between the given towns A and B.

The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km.

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 7

**Video Solution:**

## Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2

NCERT Class 10 Maths Solutions Chapter 7 Exercise 7.1 Question 2

**Summary:**

The distance between the points (0, 0) and (36, 15) is 39 km. Yes, it is possible to find the distance between the given towns A and B. The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between towns A and B will be 39 km.

**☛ Related Questions:**

- Determine if the points (1, 5), (2, 3) and (- 2, - 11) are collinear.
- Check whether (5, - 2), (6, 4) and (7, - 2) are the vertices of an isosceles triangle.
- In a classroom, 4 friends are seated at the points A, B, C and D as shown in Fig. 7.8. Champa and Chameli walk into the class and after observing for a few minutes Champa asks Chameli, “Don’t you think ABCD is a square?” Chameli disagrees. Using distance formula, find which of them is correct.
- Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer:(i) (- 1, - 2), (1, 0), (- 1, 2), (- 3, 0) (ii) (- 3, 5), (3, 1), (0, 3), (- 1, - 4) (iii) (4, 5), (7, 6), (4, 3), (1, 2)

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