Find the equation of the circle with centre (1/2, 1/4) and radius (1/12)

Solution:

The equation of a circle with centre(h, k) and radius r is given as

(x - h)² + (y - k)² = r²

It is given that centre (h, k) = (1/2, 1/4)

and radius (r ) = 1/12.

Therefore, the equation of the circle is

(x - 1/2)² + (y - 1/4)² = (1/12)²

x² - x + 1/4 + y² - y/2 + 1/16 = 1/144

x² - x + 1/4 + y² - y/2 + 1/16 - 1/144 = 0

144x² - 144x + 36 + 144 y² - 72y + 9 - 1 = 0

144x² - 144x + 144 y² - 72y + 44 = 0

36x² - 36x + 36y² - 18y + 11 = 0

36x² + 36y² - 36x - 18y + 11 = 0

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NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.1 Question 3

Find the equation of the circle with centre (1/2, 1/4) and radius (1/12)

Summary:

The equation of the circle is 36x² + 36y² - 36x - 18y + 11 = 0