Find the equation of the circle with centre (- 2, 3) and radius 4

Solution:

The equation of a circle with centre(h, k) and radius r is given as

(x - h)² + (y - k)² = r²

It is given that centre (h, k) = (- 2, 3)

and radius (r ) = 4.

Therefore,

the equation of the circle is

(x + 2)² + (y - 3)² = 4²

x² + 4x + 4 + y² - 6y + 9 = 16

x² + y² + 4x - 6y - 3 = 0

NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.1 Question 2

Find the equation of the circle with centre (- 2, 3) and radius 4

Summary:

The equation of the circle is x² + y² + 4x - 6y - 3 = 0