Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44

Solution:

The given data is 38, 70, 48, 40, 42, 55, 63, 46, 54, 44

Mean of the data

x = (38 + 70 + 48 + 40 + 42 + 55 + 63 + 46 + 54 + 44)/10

= 500/10

= 50

The deviations of the respective observations from the mean x,

i.e., x_i - x are

- 12, 20, - 2, - 10, - 8, 5, 13, - 4, 4, - 6

The absolute values of the deviations, |x_i - x| are

12, 20, 2, 10, 8, 5, 13, 4, 4, 6

M.D. (x) = ¹⁰∑_{i = 1} (|x_i - x|)/10

= (12 + 20 + 2 +10 + 8 + 5 + 13 + 4 + 4 + 6) / 10

= 84/10

= 8.4

NCERT Solutions Class 11 Maths Chapter 15 Exercise 15.1 Question 2

Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44

Summary:

The mean deviation about the mean for the given data is 8.4