from a handpicked tutor in LIVE 1-to-1 classes

# Find the points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis

**Solution:**

Given, the __equation of the line__ is 3x + 4y = 12

We have to find the points where the graph cuts the x-axis and the y-axis.

To find the graph of the equation 3x + 4y = 12 cuts the x-axis,

Put y = 0

3x + 4(0) = 12

3x = 12

x = 12/3

x = 4

Therefore, the graph cuts the x-axis at the point (4, 0)

To find the graph of the equation 3x + 4y = 12 cuts the y-axis

Put x = 0

3(0) + 4y = 12

4y = 12

y = 12/4

y = 3

Therefore, the graph cuts the y-axis at the point (0, 3)

**✦ Try This: **Find the points where the graph of the equation 5x + 4y = 20 cuts the x-axis and the y-axis.

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 4

**NCERT Exemplar Class 9 Maths Exercise 4.3 Sample Problem 1**

## Find the points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis

**Summary:**

The graph will cut the x-axis at y = 0 and the y-axis at x = 0. The points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis are (4, 0) and (0, 3)

**☛ Related Questions:**

- At what point does the graph of the linear equation x + y = 5 meet a line which is parallel to the y . . . .
- Determine the point on the graph of the equation 2x + 5y = 20 whose x-coordinate is 5/2 times its or . . . .
- Draw the graph of the equation represented by the straight line which is parallel to the x-axis and . . . .

visual curriculum