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# At what point does the graph of the linear equation x + y = 5 meet a line which is parallel to the y-axis, at a distance 2 units from the origin and in the positive direction of x-axis

**Solution:**

Given, the __linear equation__ is x + y = 5

We have to find the point at which the equation meets a line __parallel__ to the y-axis at a distance of 2 units from the origin and in the positive direction of the x-axis.

The coordinates of the point lying on the line parallel to the y-axis, at a distance x units from the origin and in the positive direction of the x-axis is given by (x, a)

Now, the distance x = 2 units

So, the coordinates of the point = (2, a)

Now put x = 2 and y = a in the given equation,

2 + a = 5

a = 5 - 2

a = 3

Therefore, the point is (2, 3)

**✦ Try This: **At what point does the graph of the linear equation x + y = 7 meet a line which is parallel to the y-axis, at a distance 4 units from the origin and in the positive direction of x-axis.

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 4

**NCERT Exemplar Class 9 Maths Exercise 4.3 Sample Problem 2**

## At what point does the graph of the linear equation x + y = 5 meet a line which is parallel to the y-axis, at a distance 2 units from the origin and in the positive direction of x-axis

**Summary:**

The point at which the equation meets a line parallel to the y-axis at a distance of 2 units from the origin and in the positive direction of the x-axis is (2, 3)

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