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# Find the smallest square number that is divisible by each of the numbers 4, 9 and 10

**Solution:**

The number that will be perfectly divisible by each of the numbers 4, 9 and 10 will be their LCM.

LCM of 4, 9, 10

= 2 × 2 × 3 × 3 × 5

= 180

Here, the prime factor 5 does not have a pair. Therefore 180 is multiplied by 5 then the number obtained is a perfect square.

Thus, 180 × 5 = 900

So, 900 is the smallest square that is divisible by 4, 9, and 10

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 6

**Video Solution:**

## Find the smallest square number that is divisible by each of the numbers 4, 9 and 10

NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.3 Question 9

**Summary:**

The smallest perfect square number that is divisible each by 4, 9 and 10 is 900

**☛ Related Questions:**

- For each of the following numbers, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained. (i) 252 (ii) 180 (iii) 1008 (iv) 2028 (v) 1458 (vi) 768
- For each of the following numbers, find the smallest whole number by which it should be divided so as to get a perfect square. Also find the square root of the square number so obtained. (i) 252 (ii) 2925 (iii) 396 (iv) 2645 (v) 2800 (vi) 1620
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