# Find the smallest square number that is divisible by each of the numbers 8, 15 and 20

**Solution:**

The number that will be perfectly divisible by each of the numbers 8, 15, and 20 will be their LCM.

LCM of 8,15, 20

= 2 × 2 × 2 × 3 × 5

= 120

Here we see that prime factors 2, 3, 5 do not have their respective pairs.

Therefore 120 is not a perfect square.

If 120 is multiplied by 2 × 3 × 5, then the number obtained will be a perfect square.

Therefore, 120 × 2 × 3 × 5 = 3600

Thus, the perfect square number is 3600 which is completely divisible by 8, 15, and 20.

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 6

**Video Solution:**

## Find the smallest square number that is divisible by each of the numbers 8, 15 and 20

NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.3 Question 10

**Summary:**

The smallest perfect square number that is divisible each by 8, 15 and 20 is 3600

**☛ Related Questions:**

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