# If A = {x : x is a natural number }, B = {x : x is an even natural number} C = {x : x is an odd natural number}andD = {x : x is a prime number }, find (i) A ∩ B (ii) A ∩ C (iii) A ∩ D (iv) B ∩ C (v) B ∩ D (vi) C ∩ D

**Solutions:**

A = {x : x is a natural number} = {1, 2, 3, 4, 5....}

B = {x : x is an even natural number} = {2, 4, 6,8....}

C = {x : x is an odd natural number} = {1, 3, 5, 7, 9....}

D = {x : x is a prime number} = {2, 3, 5, 7....}

(i) A ∩ B = {x : x is a even natural number}

= B

(ii) A ∩ C = {x : x is an odd natural number}

= C

(iii) A ∩ D = {x : x is a prime number}

= D

(iv) B ∩ C = Φ

(v) B ∩ D = {2}

(vi) C ∩ D = {x : x is an odd prime number}

NCERT Solutions Class 11 Maths Chapter 1 Exercise 1.4 Question 7

## If A = {x : x is a natural number }, B = {x : x is an even natural number} C = {x : x is an odd natural number}andD = {x : x is a prime number }, find (i) A ∩ B (ii) A ∩ C (iii) A ∩ D (iv) B ∩ C (v) B ∩ D (vi) C ∩ D

**Summary:**

It is given that A = { x : x is a natural number} and B = { x : x is an even natural number}. We have found that A ∩ B = {x : x is a even natural number} = B.

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