# In the following figures, find the area of the shaded portions:

**Solution:**

(i) Area of ∆ AEF = 1/2 × Base × Height

= 1/2 × 6 cm × 10 cm

= 30 cm^{2}

Area of ∆ BCE = 1/2 × Base × Height

= 1/2 × 8 cm × 10 cm

= 40 cm^{2}

Area of rectangle ABCD = Length × Breadth

= 18 cm × 10 cm

= 180 cm^{2}

Area of shaded region = Area of rectangle ABCD - (Area of ∆ AEF + Area of ∆ BEC)

= 180 cm^{2} - (30 cm^{2} + 40 cm^{2})

= 180 cm^{2} - 70 cm^{2}

= 110 cm^{2}

(ii) Area of ∆ PQT = 1/2 × Base × Height

= 1/2 × 20 cm × 10 cm

= 100 cm^{2}

Area of ∆ QRU = 1/2 × Base × Height

= 1/2 × 10 cm × 20 cm

= 100 cm^{2}

Area of ∆ STU = 1/2 × Base × Height

= 1/2 × 10 cm × 10 cm

= 50 cm^{2}

Area of square PQRS = Side × Side

= 20 cm × 20 cm

= 400 cm^{2}

Area of shaded region = Area of square PQRS - (Area of ∆ PQT + Area of ∆ QRU + Area of ∆ STU)

= 400 cm^{2} - (100 cm^{2} +100 cm^{2} + 50 cm^{2} )

= 400 cm^{2} - 250 cm^{2}

= 150 cm^{2}

**☛ Check: **NCERT Solutions Class 7 Maths Chapter 11

**Video Solution:**

## In the following figures, find the area of the shaded portion:

Maths NCERT Solutions Class 7 Chapter 11 Exercise 11.4 Question 10

**Summary:**

In the following figures, the area of the shaded portions is 110 cm^{2} and 150 cm^{2} respectively.

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