# Let A = {9, 10, 11, 12, 13} and let f : A → N be defined by f (n) = the highest prime factor of n. Find the range of f

**Solution**:

It is given that

A = {9, 10, 11, 12, 13} and f : A → N is defined by

f (n) = the highest prime factor of n

Hence,

Prime factor of 9 = 3

Prime factor of 10 = 2, 5

Prime factor of 11 = 11

Prime factor of 12 = 2, 3

Prime factor of 13 = 13

Therefore,

f (9) = the highest prime factor of 9 = 3

f (10) = the highest prime factor of 10 = 5

f (11) = the highest prime factor of 11 = 11

f (12) = the highest prime factor of 12 = 3

f (13) = the highest prime factor of 13 = 13

The range of f is the set of all f (n), where n ∈ A.

Therefore, Range of f = {3, 5, 11, 13}

NCERT Solutions Class 11 Maths Chapter 2 Exercise ME Question 12

## Let A = {9, 10, 11, 12, 13} and let f : A → N be defined by f (n) = the highest prime factor of n. Find the range of f

**Summary:**

A relation given by A = {9, 10, 11, 12, 13} and f : A → N be defined by f (n) = the highest prime factor of n. Range of f = {3, 5, 11, 13}.

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