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# Multiply: (3x² + 4x - 8), (2x² - 4x + 3)

**Solution:**

Given, __multiply__ (3x² + 4x - 8), (2x² - 4x + 3)

⇒ (3x² + 4x - 8) × (2x² - 4x + 3)

= 6x⁴ - 12x³ + 9x² + 8x³ - 16x² + 12x - 16x² + 32x - 24

= 6x⁴ - 12x³ + 8x³ + 9x² - 16x² - 16x² + 12x + 32x - 24

= 6x⁴ - 4x³ - 23x² + 44x - 24

**✦ Try This: **Multiply: (4a² + 5a - 8), (3a² + 4a - 3)

Given, Multiply: (4a² + 5a - 8), (3a² + 4a - 3)

⇒ (4a² + 5a - 8) × (3a² + 4a - 3)

= 12a⁴ + 16a³ - 12a² + 15a³ + 20a² - 15a - 24a² - 32a + 24

= 12a⁴ + 31a³ -16a² - 47a + 24

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 9

**NCERT Exemplar Class 8 Maths Chapter 7 Problem 83(xxi)**

## Multiply: (3x² + 4x - 8), (2x² - 4x + 3)

**Summary:**

Multiplying (3x² + 4x - 8), (2x² - 4x + 3) we get, 6x⁴ - 4x³ - 23x² + 44x - 24

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