# Prove that: 1) sin²π/6 + cos²π/3 – tan²π/4 = -1/ 2

**Solution:**

We know that the cos π/3 = 1/2, sin π/6 = 1/2, and tan π/4 = 1 (by trigonometric table).

Substituting these values in the LHS,

LHS = sin²π/6 + cos²π/3 – tan²π/4

= (1/2)^{2}+(1/2)^{2}-(1)^{2}

= (1/4) + (1/4) - 1

= -1/2

= RHS.

NCERT Solutions Class 11 Maths Chapter 3 Exercise 3.3 Question 1

## Prove that: 1) sin²π/6 + cos²π/3 – tan²π/4 = -1/ 2

**Summary:**

We got, sin^{2}π/6 + cos^{2}π/3 – tan^{2}π/4 = -1/ 2 , Hence Proved