Prove that the following functions do not have maxima or minima:
(i) f (x) = ex (ii) g (x) = log x (iii) h (x) = x3 + x2 + x + 1
Solution:
Maxima and minima are known as the extrema of a function.
Maxima and minima are the maximum or the minimum value of a function within the given set of ranges.
According to the given question.
(i) f (x) = ex
f' (x) = ex
Now,
f' (x) = 0
⇒ ex = 0
But the exponential function can never assume 0 for any value of x.
Therefore, there does not exist c ∈ R such that f' (c) = 0
Hence, function f does not have maxima or minima.
(ii) g (x) = log x
Therefore,
g' (x) = 1/x
Since log x is defined for a positive number x, g' (x) > 0 for any x.
Therefore, there does not exist c ∈ R such that g' (c) = 0.
Hence, function g does not have maxima or minima.
(iii) h (x) = x3 + x2 + x + 1
Therefore,
h' (x) = 3x2 + 2x + 1
Now,
h' (x) = 0
⇒ 3x2 + 2x + 1 = 0
⇒ x = (- 2 ± √2i) / 6
⇒ x = (- 1 ± √2i) / 3 ≠ R.
Therefore, there does not exist c ∈ R such that h' (c) = 0.
Hence, function h does not have maxima or minima
NCERT Solutions Class 12 Maths - Chapter 6 Exercise 6.5 Question 4
Prove that the following functions do not have maxima or minima: (i) f (x) = ex (ii) g (x) = log x (iii) h (x) = x3 + x2 + x + 1
Summary:
i)There does not exist c ∈ R such that f' (c) = 0.Hence, function f does not have maxima or minima. Maxima and minima are the maximum or the minimum value of a function within the given set of ranges
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