# Rukhsar painted the outside of the cabinet of measure 1 m × 2 m × 1.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?

**Solution:**

The surface area of the bottom of the cuboid will be subtracted from the total surface area of the cabinet.

From the given figure,

Length 'l' of the cabinet = 2 m

Breadth 'b' of the cabinet = 1 m

Height 'h' of the cabinet = 1.5 m

Area of the bottom of cabinet = l × b

Since the cabinet is cuboidal in shape,

Total surface area of the cabinet = 2(l × b + b × h + h × l)

Area of the cabinet that was painted = (Total surface area of the cabinet) - (Area of bottom of the cabinet)

= 2(l × b + b × h + h × l) − l × b

= 2(b × h + h × l) + l × b

= 2 × (1 × 1.5 + 1.5 × 2) + 2 × 1 m²

= 2 × 4.5 + 2 m²

= 11 m²

Therefore the area of the cabinet that was painted is 11 m².

**Video Solution:**

## Rukhsar painted the outside of the cabinet of measure 1 m × 2 m × 1.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?

### Maths NCERT Solutions Class 8 - Chapter 11 Exercise 11.3 Question 4

**Summary:**

Rukhsar painted the outside of the cabinet of measure 1 m × 2 m × 1.5 m. The surface area that she covered if she painted all except the bottom of the cabinet was 11 m².