# Solve:

(i) 2 - (3/5) (ii) 4 + (7/8) (iii) (3/5) + (2/7)

(iv) (9/11) - (4/15) (v) (7/10) + (2/5) + (3/2)

(vi) \(2{\Large\frac{2}{3}}\) + \(3{\Large\frac{1}{2}}\) (vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\)

**Solution:**

Let's use the concept of addition and subtraction of fractions here.

(i) 2 - (3/5)

2 - 3/5

= 2/1 - 3/5

= (10 - 3)/5

= 7/5

(ii) 4 + (7/8)

= 4 + 7/8

= 4/1 + 7/8

= (32 + 7)/8

= 39/8

(iii) (3/5) + (2/7)

= 3/5 + 2/7

= (21 + 10)/35

= 31/35

(iv) (9/11) - (4/15)

= 9/11 - 4/15

= (135 - 44)/165

= 91/165

(v) (7/10) + (2/5) + (3/2)

= 7/10 + 2/5 + 3/2

= (7 + 4 + 15)/10

= 26/10

= 13/5

(vi) \(2{\Large\frac{2}{3}}\) + \(3{\Large\frac{1}{2}}\)

= 8/3 + 7/2

= (16 + 21)/6

= 37/6

(vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\)

= 17/2 - 29/8

= (68 - 29/8)

= 39/8

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 2

**Video Solution:**

## Solve: (i) 2 - (3/5) (ii) 4 + (7/8) (iii) (3/5) + (2/7) (iv) (9/11) - (4/15) (v) (7/10) + (2/5) + (3/2) (vi) \(2{\Large\frac{2}{3}}\) + \(3{\Large\frac{1}{2}}\) (vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\)

NCERT Solutions Class 7 Maths Chapter 2 Exercise 2.1 Question 1

**Summary:**

The values of the following: (i) 2 - (3/5) (ii) 4 + (7/8) (iii) (3/5) + (2/7) (iv) (9/11) - (4/15) (v) (7/10) + (2/5) + (3/2) (vi) \(2{\Large\frac{2}{3}}\)+ \(3{\Large\frac{1}{2}}\) (vii) \(8{\Large\frac{1}{2}}\) - \(3{\Large\frac{5}{8}}\) are (i) 7/5 (ii) 39/8 (iii) 31/35 (iv) 91/165 (v) 13/5 (vi) 37/6 and (vii) 39/8 respectively.

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