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# The decimal expansion of the number √2 is

a. a finite decimal

b. 1.41421

c. non-terminating recurring

d. non-terminating non-recurring

**Solution:**

We know that

√2 = 1.41421

A number which cannot be expressed in the form p/q where p and q are __integers__ and q ≠ 0 is called an __irrational number__.

Here √2 is an irrational number

So the decimal expansion is __non terminating__ and non recurring.

Therefore, the decimal expansion is non-terminating and non-recurring.

**✦ Try This: **Find a rational number between 7/6 and 5/6.

Rational numbers between 7/6 and 5/6 can be written as

(7/6 + 5/6)/2

Taking LCM

= [(7 + 5)/6]/2

By further calculation

= (12/6)/2

= 2 × 1/2

= 1

Therefore, the rational number is 1.

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 1

**NCERT Exemplar Class 9 Maths Exercise 1.1 Problem 5**

## The decimal expansion of the number √2 is a. finite decimal, b. 1.41421, c. non-terminating recurring, d. non-terminating non-recurring

**Summary**:

The decimal expansion of the number √2 is non-terminating non-recurring. As √2 = 1.41421 the decimal expansion is non-terminating non-recurring

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