# The median of an ungrouped data and the median calculated when the same data is grouped are always the same. Do you think that this is a correct statement? Give reason

**Solution:**

To calculate the median of a grouped data the formula which is used is based on the assumption that the observations in the classes are equally spaced or uniformly distributed

So the statement is not always correct.

Therefore, the statement is not correct.

**✦ Try This: **If A and B are two independent events, the probability that both A and B occur is 2/8 and the probability that neither of them occurs is 4/8, The probability of the occurrence of A is

Consider P(A) = x and P (B) = y

xy = 2/8

(1 - x) (1 - y) = 4/8

By further simplification

1 - x - y + xy = 4/8

Substituting the value of xy

1 - x - y + 2/8 = 4/8

1 - x - y = 4/8 - 2/8

1 - x - y = 2/8

1 - x - y = 1/4

x + y = 1 - 1/4 = 3/4

So x and y can take values 0.5 and 0.25

Therefore, the probability of occurrence of A is 1/2 and 1/4.

**☛ Also Check: **NCERT Solutions for Class 10 Maths Chapter 14

**NCERT Exemplar Class 10 Maths Exercise 13.2 ****Problem 1**

## The median of an ungrouped data and the median calculated when the same data is grouped are always the same. Do you think that this is a correct statement? Give reason

**Summary:**

The statement “The median of an ungrouped data and the median calculated when the same data is grouped are always the same” is not correct

**☛ Related Questions:**

- In calculating the mean of grouped data, grouped in classes of equal width, we may use the formula x . . . .
- Is it true to say that the mean, mode and median of grouped data will always be different? Justify y . . . .
- Will the median class and modal class of grouped data always be different? Justify your answer

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