The square root of a perfect square of n digits will have (n+1)/2 digits, if n is odd. State whether the statement is true or false.
Solution:
Given, the square root of a perfect square of n digits will have (n+1)/2 digits, if n is odd.
We have to determine if the given statement is true or false.
Example: consider a perfect square 625
Number of digits, n = 3
n is odd, number of digits in square root = (3+1)/2
= 4/2
= 2
Verification: Square root of 625 = √(25)²
= 25
Number of digits = 2
Therefore, the square root of a perfect square of n digits will have (n+1)/2 digits, if n is odd
✦ Try This: The square root of a perfect square of n digits will have n/2 digits, if n is even. State whether the statement is true or false.
☛ Also Check: NCERT Solutions for Class 8 Maths
NCERT Exemplar Class 8 Maths Chapter 3 Problem 72
The square root of a perfect square of n digits will have (n+1)/2 digits, if n is odd. State whether the statement is true or false
Summary:
The given statement, ”The square root of a perfect square of n digits will have (n+1)/2 digits, if n is odd” is true.
☛ Related Questions:
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