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Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops
We know that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
AB is the height of one pole = 6m
CD is the height of another pole = 11m
AC is the distance between two poles at bottom = 12m
BD is the distance between the tops of the poles = ?
Draw BE || AC
Now consider, in Δ BED
∠BED = 90°
BE = AC = 12 m
DE = CD - CE
DE = 11 - 6 = 5 cm
BD2 = BE2 + DE2 (Pythagoras therorem)
BD2 = 122 + 52
BD2 = 144 + 25
BD2 = 169
BD = 13m
The distance between the top of the poles is 13 m.
☛ Check: NCERT Solutions for Class 10 Maths Chapter 6
Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.
NCERT Class 10 Maths Solutions Chapter 6 Exercise 6.5 Question 12
Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, then the distance between their tops is 13 m.
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