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# What can the maximum number of digits be in the repeating block of digits in the decimal expansion of 1/17? Perform the division to check your answer.

**Solution:**

Let us perform long division to find the value of 1/17 as shown below.

Thus, we finally end up with remainder as 1 from where the digits in the quotient will again start repeating i.e, 0.0588235294117647058823...

Hence, there are 16 digits in the repeating block of the decimal expansion of 1/17.

**☛ Check: **NCERT Solutions Class 9 Maths Chapter 1

**Video Solution:**

## What can the maximum number of digits be in the repeating block of digits in the decimal expansion of 1/17? Perform the division to check your answer.

NCERT Solutions Class 9 Maths Chapter 1 Exercise 1.3 Question 5

**Summary:**

The decimal expansion of 1/17 is 0.0588235294117647...Thus, the maximum number of digits in the repeating block of digits in the decimal expansion of 1/17 is 16.

**☛ Related Questions:**

- Write the following in decimal form and say what kind of decimal expansion each has: i) 36/100 ii) 1/11 iii) 4 1/8 iv) 3/13 v) 2/11 vi) 329/400
- You know that 1/7 = 0.142587. Can you predict what the decimal expansions of 2/7, 3/7, 4/7, 5/7, 6/7 are, without actually doing the long division? If so, how?
- Express the following in the form of p/q, where p and q are integers and q ≠ 0. i) 0.6 ii) 0.47 iii) 0.001
- Express 0.99999 .... in the form of p/q. Are you surprised with your answer? With your teacher and classmates discuss why the answer makes sense?

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