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# A function f(x) has x-intercept of -3 and -5. What is the constant term in the function? f(x) = x^{2} + 8x + ___

**Solution:**

Given: Function f(x) = x^{2} + 8x + ___

Let us consider the constant term as b

f(x) = x^{2} + 8x + b

Where b is the y intercept or the constant term

We know that,

X-intercept is the value of x when the function value is zero

For x = -3 we get f(x) =0

For x = -5 we get f(x) = 0

By substituting one of the intercepts in the given function

f(-3) = (-3)^{2} + 8(-3) + b

0 = 9 - 24 + b

0 = -15 + b

b = 15

f(x) = x^{2} + 8x + 15

Therefore, the constant term in the function is 15.

## A function f(x) has x-intercept of -3 and -5. What is the constant term in the function? f(x) = x^{2} + 8x + ___

**Summary:**

A function f(x) has x-intercept of -3 and -5. The constant term in the function f(x) = x^{2} + 8x + ___ is 15.

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