By how much does a³ - 2a exceed a² + a - 6?

Solution:

Given, the expressions are 

a³ - 2a and a² + a - 6

We have to find how much a³ - 2a exceed a² + a - 6

This implies we have to subtract the two expressions.

So, (a³ - 2a) - (a² + a - 6) 

Removing the parentheses

= a³ - 2a - a² - a + 6

By grouping of common terms,

= a³ - a² - 2a - a + 6

So we get

= a³ - a² - 3a + 6

Therefore, a³ - 2a exceed a² + a - 6 by a³ - a² - 3a + 6

By how much does a³ - 2a exceed a² + a - 6?

Summary:

By a³ - a² - 3a + 6, a³ - 2a exceed a² + a - 6.