A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Choose the solution(s) of the following system of equations: x2 + y2 = 6 and x2 - y = 6
No solution, (√6, 0), (√5, 1), (√5, -1), Infinitely many solutions, (-√6, 0), (-√5, 1), (-√5, -1)
Solution:
Given: Linear equations are x2 + y2 = 6 and x2 - y = 6
In order to find solution, we need to eliminate one variable to find the other
Let x2 + y2 = 6 --- (a)
x2 - y = 6 --- (b)
Subtract eq(b) from eq(a)
We get, y2 + y =0
⇒ y(y + 1) = 0
⇒ y = 0, -1
When y = 0, x2 = 6
⇒ x = √6, -√6
When y = -1, x2 = 5
⇒ x = √5, -√5
Therefore, the solutions are (√6, 0), (-√6, 0), (√5, -1), (-√5, -1).
Choose the solution(s) of the following system of equations: x2 + y2 = 6 and x2 - y = 6
Summary:
The solution(s) of the following system of equations: x2 + y2 = 6 and x2 - y = 6 are (√6, 0), (-√6, 0), (√5, -1), (-√5, -1).
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