Consider the following function. f(x) = 1 - x^2/3 Find f(-1) and f(1).

Solution:

Given function f(x) = 1 - x^2/3

∴ f(-1) = 1 - (-1)^2/3

= 1 - [(-1)²]^1/3

= 1 - (1)^1/3

= 0

∴ f(1) = 1 - (1)^2/3

= 1 - [(1)²]^1/3

= 1 - (1)^1/3

= 0

Example: If f(x) = x² - 3x + 1 then find the value of f(2) , f(-3)

Given, f(x) = x² - 3x + 1

f(2) = 2² - 3(2) + 1= 4 - 6 + 1 = -1

f(-3) =(-3)² - 3(-3) + 1 = 9 + 9 + 1 = 19

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Consider the following function. f(x) = 1 - x^2/3 Find f(-1) and f(1).

Summary:

If the function f(x) = 1 - x^2/3 then f(-1) = 0 and f(1) = 0.