# Factor x^{2} - 7x + 8.

(x + 8)(x - 1), Irrational numbers, (x - 8)(x - 1), (x + 8)(x + 1)

**Solution:**

Given x^{2} - 7x + 8

This is quadratic equation in the form of ax^{2} + bx + c = 0

a = 1; b = -7; c = 8

x = {-b ± √(b^{2} - 4ac)}/2a

= {-(-7) ± √((-7)^{2} - 4(1)(8))}/2(1)

= { 7 ± √(49 - 32)}/2

= {-7 ± √17}/2

We got factors as irrational numbers.

## Factor x^{2} - 7x + 8.

**Summary:**

By factoring x^{2} - 7x + 8, we got factors as irrational numbers.

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