Find 3 consecutive even numbers such that the sum of the first and last numbers exceed the second number by 10.

An even number is a number that is a multiple of 2.

Answer: The 3 Consecutive even numbers such that the sum of first and last numbers exceed the second number by 10 are 8,10 and 12

Let's find those 3 consecutive even numbers.

Explanation:

Let the three consecutive even numbers be x, (x + 2) and (x + 4)

According to the question, 

First number + Last number  = Second number + 10

x + x + 4 = x + 2 + 10

2x + 4 = x + 12

2x - x = 12 - 4

x = 8

Thus, the numbers are x = 8,

x + 2 = 10 and

x + 4 = 12

Thus, The 3 consecutive even numbers such that sum of first and last numbers exceed second number by 10 are 8, 10 and 12.