Find -a² - 3b³ + c² + 2b³ - c² if a = 3, b = 2, and c = -3.?

Solution:

Given: -a² - 3b³ + c² + 2b³ - c²  is an algebraic expression.

Grouping the like terms and adding them, we get

= (-3b³ + 2b³)+ (-c² + c²) - a² = - b³ - a² --- (1)

Substituting the values given, b = 2, and c = -3

-(2)³ - (3)²

= -8 -9

= -17

Find -a² - 3b³ + c² + 2b³ - c² if a = 3, b = 2, and c = -3.?

Summary:

The value of the given equation -a² - 3b³ + c² + 2b³ - c² if a = 3, b = 2, and c = -3 is -17.