Find the 30th term of the following sequence. 1, 7, 13, 19, …

Solution:

The given series is an arithmetic progression.

The first term a = 1

The common difference d = 6

The nth term is

Tn = a + (n - 1)d

T₃₀ = 1 + (30 - 1)6 = 1 + (29)(6) = 1 + 174 = 175

Find the 30th term of the following sequence. 1, 7, 13, 19, …

Summary:

The 30th term of the following sequence. 1, 7, 13, 19, is 175