Find the 31st term of the following sequence. 9, 15, 21, …

Solution:

Given sequence 9, 15, 21......

The second term is 6 added to the first term

The third term is 6 added to the second term

Hence, we can say that the above sequence is in arithmetic progression,

Where the first term a = 9, and the common difference d = 6

Arithmetic progression is defined as the sequence of numbers which differs by a constant number from the preceding term

We know that the formula to calculate nth term in A.P. is given as

T_n = a + (n - 1)d

So, 31st term T₃₁ = 9 + (31 - 1)(6)

T₃₁ = 9 + 30(6)

T₃₁ = 9 + 180

T₃₁ = 189

Therefore, the 31st term in the given sequence is 189.

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Find the 31st term of the following sequence. 9, 15, 21, …

Summary:

The 31st term of the following sequence. 9, 15, 21, … is 189.