Find the diagonal of a square whose sides are of the given measure. given = 3 square root of 2

Solution:

It is given that

Sides of a square = 3√2

By using the Pythagoras theorem, let us find the diagonal 

d² = (3√2)² + (3√2)²

By further calculation

d² = 18 + 18 

By addition 

d² = 36

So we get

d = √36 = 6

Therefore, the measure of the diagonal is 6.

Find the diagonal of a square whose sides are of the given measure. given = 3 square root of 2

Summary:

The diagonal of a square whose sides are of the given measure 3 square root of 2 is 6.