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# Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).

**Solution:**

It is given that pair of points. (6, -1), (-3, 2).

The slope of the Line that Passes Through (x_{1}, y_{1}) and (x_{2}, y_{2}) is given by:

Slope (m) = (y_{2} - y_{1}) / (x_{2} - x_{1})

So, (x_{1}, y_{1}) = (6, -1) and (x_{2}, y_{2}) = (-3, 2)

Now, Substitute (x_{1}, y_{1}) and (x_{2}, y_{2}) with their given values, we get,

m = (- 1 - 2)/(6 - (-3))

m = (-3) / (9)

m = -1/3

Now use the slope and point (2, 3) to find the y-intercept.

y = mx + b

⇒ -1 = (-1/3)(6) + b

⇒ -1 = -6/3 + b

⇒ -1 = -2 + b

⇒ b = 2 - 1

⇒ b = 1

So, y = -1/3x + 1

Therefore, the equation of the line is y= -1/3x + 1.

## Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).

**Summary:**

The equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2) is y = -1/3x + 1.

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