For the following system of equations what is the x-value of the solution -x + 2y = 6; 6y = x + 18
Solutions:
Given set of equations -x + 2y = 6; 6y = x + 18
In order to eliminate one variable, we need to perform addition or subtraction of the equations
Let -x + 2y = 6 --- [a]
Let 6y = x + 18 --- [b]
Rearrange equation [b] like -x + 6y = 18
Now subtract eq[b] from [a]
⇒ (-x + 2y) - (-x + 6y) = (6 - 18)
⇒ -x + 2y + x - 6y = -12
⇒ -4y = -12
⇒ 4y = 12
⇒ y = 3
Put y = 3 in eq[a], we get -x + 2(3) = 6
⇒ -x + 6 = 6
⇒ x = 0
Therefore, the value of x is 0.
For the following system of equations what is the x-value of the solution -x + 2y = 6; 6y = x + 18
Summary:
For the following system of equations, the x-value of the solution -x + 2y = 6; 6y = x + 18 is zero.
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