Graph the first six terms of a sequence where a₁ = 3 and d = -10.

Solution:

It is given that

First term a₁ = 3

Common difference d = -10

The formula to find the terms of the sequence is

a_n = a + (n - 1)d

Where a_n is the nth term of series

a is the first term

n is the number of terms

d is the common difference

When n = 2

a₂ = 3 + (2 - 1)(-10)

a₂ = 3 + (1)(-10)

a₂ = 3 - 10

a₂ = -7

When n = 3

a₃ = 3 + (3 - 1)(-10)

a₃ = 3 + (2)(-10)

a₃ = 3 - 20

a₃ = -17

When n = 4

a₄ = 3 + (4 - 1)(-10)

a₄ = 3 + (3)(-10)

a₄ = 3 - 30

a₄ = -27

When n = 5

a₅ = 3 + (5 - 1)(-10)

a₅ = 3 + (4)(-10)

a₅ = 3 - 40

a₅ = -37

When n = 6

a₆ = 3 + (6 - 1)(-10)

a₆ = 3 + (5)(-10)

a₆ = 3 - 50

a₆ = -47

Therefore, the graph of the first six terms is mentioned above.

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Graph the first six terms of a sequence where a₁ = 3 and d = -10.

Summary:

The graph of the first six terms of a sequence where a₁ = 3 and d = -10 is mentioned above.