How do you find an equation of the line having the given slope and containing the given point m = -8, (4, 5)?

Solution:

Given, slope m = -8

The point is (4, 5)

We have to find an equation of the line

The equation of the line in slope-intercept form is given by

y = mx + b

Where, m is the slope.

Here, m = -8 and (x, y) = (4, 5)

5 = -8(4) + b

5 = -32 + b

b = 5 + 32

b = 37

So, y = -8x + 37

Therefore, the equation of the line is y = -8x + 37.

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How do you find an equation of the line having the given slope and containing the given point m = -8, (4, 5)?

Summary:

An equation of the line having the given slope and containing the given point m = -8, (4, 5) is y = -8x + 37.