# Identify the factors of x^{2} - 8x - 20 = 0

**Solution:**

Given quadratic equation x^{2} - 8x - 20 = 0 is in the form of ax^{2} + bx + c = 0

Solving the equation by factorizing

We know the roots of the general form ax^{2} + bx + c = 0 are α and β as the sum of its roots (α + β) = -b/a , and the product of its roots (αβ) = c/a .

Now,

First split the middle term -8x into -10x and +2x as -10x + 2x = -8x and

(-10x)(2x)= -20x^{2}

=> x^{2} - 8x - 20 = 0

=> x^{2} - 10x + 2x - 20 = 0

=> x(x - 10) +2(x - 10) = 0

=> (x + 2)(x - 10) = 0

=>∴ The factors are (x+2) and (x-10)

## Identify the factors of x^{2} - 8x - 20 = 0

**Summary:**

The factors of the given quadratic equation x^{2} - 8x - 20 = 0 are (x + 2) and (x - 10).