If Bill and Hanes have 60 dollars between them, and Hanes has half as much as Bill, how much does Hanes have?

Solution:

Given:

Dollars with Bill & Hanes = 60 dollars

Dollars with Hanes = 1/2 of dollars with Bill 

Let us write these mathematical equations into algebraic expressions.

Let the amount with Bill be x 

the amount with Hanes be y

x + y = 60 dollars -------->(1)

y = 1/2 × x-------->(2)

Substituting equation (2) in (1)

x + 1/2 × x = 60

Taking LCM

3/2 × x = 60

x = 2/3 × 60

So we get

x = 40 dollars

Bill has 40 dollars.

Substituting it in equation (1)

40 + y = 60

y = 60 - 40 = 20 dollars

Therefore, Hanes has $20

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If Bill and Hanes have 60 dollars between them, and Hanes has half as much as Bill, how much does Hanes have?

Summary:

If Bill and Hanes have 60 dollars between them, and Hanes has half as much as Bill, Hanes has 20 dollars.